3.1.22 \(\int \frac {\log ^2(e (f (a+b x)^p (c+d x)^q)^r)}{(a+b x)^3} \, dx\) [22]

3.1.22.1 Optimal result
3.1.22.2 Mathematica [A] (verified)
3.1.22.3 Rubi [A] (verified)
3.1.22.4 Maple [F]
3.1.22.5 Fricas [F]
3.1.22.6 Sympy [F]
3.1.22.7 Maxima [A] (verification not implemented)
3.1.22.8 Giac [F]
3.1.22.9 Mupad [F(-1)]

3.1.22.1 Optimal result

Integrand size = 31, antiderivative size = 632 \[ \int \frac {\log ^2\left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{(a+b x)^3} \, dx=-\frac {p^2 r^2}{4 b (a+b x)^2}-\frac {3 d p q r^2}{2 b (b c-a d) (a+b x)}-\frac {d^2 p q r^2 \log (a+b x)}{2 b (b c-a d)^2}+\frac {d^2 q^2 r^2 \log (a+b x)}{b (b c-a d)^2}+\frac {d^2 p q r^2 \log ^2(a+b x)}{2 b (b c-a d)^2}+\frac {d^2 p q r^2 \log (c+d x)}{2 b (b c-a d)^2}-\frac {d^2 q^2 r^2 \log (c+d x)}{b (b c-a d)^2}-\frac {d^2 p q r^2 \log \left (-\frac {d (a+b x)}{b c-a d}\right ) \log (c+d x)}{b (b c-a d)^2}-\frac {d^2 q^2 r^2 \log ^2(c+d x)}{2 b (b c-a d)^2}+\frac {d^2 q^2 r^2 \log (a+b x) \log \left (\frac {b (c+d x)}{b c-a d}\right )}{b (b c-a d)^2}-\frac {p r \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{2 b (a+b x)^2}-\frac {d q r \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{b (b c-a d) (a+b x)}-\frac {d^2 q r \log (a+b x) \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{b (b c-a d)^2}+\frac {d^2 q r \log (c+d x) \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{b (b c-a d)^2}-\frac {\log ^2\left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{2 b (a+b x)^2}+\frac {d^2 q^2 r^2 \operatorname {PolyLog}\left (2,-\frac {d (a+b x)}{b c-a d}\right )}{b (b c-a d)^2}-\frac {d^2 p q r^2 \operatorname {PolyLog}\left (2,\frac {b (c+d x)}{b c-a d}\right )}{b (b c-a d)^2} \]

output
-1/4*p^2*r^2/b/(b*x+a)^2-3/2*d*p*q*r^2/b/(-a*d+b*c)/(b*x+a)-1/2*d^2*p*q*r^ 
2*ln(b*x+a)/b/(-a*d+b*c)^2+d^2*q^2*r^2*ln(b*x+a)/b/(-a*d+b*c)^2+1/2*d^2*p* 
q*r^2*ln(b*x+a)^2/b/(-a*d+b*c)^2+1/2*d^2*p*q*r^2*ln(d*x+c)/b/(-a*d+b*c)^2- 
d^2*q^2*r^2*ln(d*x+c)/b/(-a*d+b*c)^2-d^2*p*q*r^2*ln(-d*(b*x+a)/(-a*d+b*c)) 
*ln(d*x+c)/b/(-a*d+b*c)^2-1/2*d^2*q^2*r^2*ln(d*x+c)^2/b/(-a*d+b*c)^2+d^2*q 
^2*r^2*ln(b*x+a)*ln(b*(d*x+c)/(-a*d+b*c))/b/(-a*d+b*c)^2-1/2*p*r*ln(e*(f*( 
b*x+a)^p*(d*x+c)^q)^r)/b/(b*x+a)^2-d*q*r*ln(e*(f*(b*x+a)^p*(d*x+c)^q)^r)/b 
/(-a*d+b*c)/(b*x+a)-d^2*q*r*ln(b*x+a)*ln(e*(f*(b*x+a)^p*(d*x+c)^q)^r)/b/(- 
a*d+b*c)^2+d^2*q*r*ln(d*x+c)*ln(e*(f*(b*x+a)^p*(d*x+c)^q)^r)/b/(-a*d+b*c)^ 
2-1/2*ln(e*(f*(b*x+a)^p*(d*x+c)^q)^r)^2/b/(b*x+a)^2+d^2*q^2*r^2*polylog(2, 
-d*(b*x+a)/(-a*d+b*c))/b/(-a*d+b*c)^2-d^2*p*q*r^2*polylog(2,b*(d*x+c)/(-a* 
d+b*c))/b/(-a*d+b*c)^2
 
3.1.22.2 Mathematica [A] (verified)

Time = 0.62 (sec) , antiderivative size = 872, normalized size of antiderivative = 1.38 \[ \int \frac {\log ^2\left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{(a+b x)^3} \, dx=-\frac {b^2 c^2 p^2 r^2-2 a b c d p^2 r^2+a^2 d^2 p^2 r^2+6 a b c d p q r^2-6 a^2 d^2 p q r^2+6 b^2 c d p q r^2 x-6 a b d^2 p q r^2 x-2 d^2 p q r^2 (a+b x)^2 \log ^2(a+b x)-2 a^2 d^2 p q r^2 \log (c+d x)+4 a^2 d^2 q^2 r^2 \log (c+d x)-4 a b d^2 p q r^2 x \log (c+d x)+8 a b d^2 q^2 r^2 x \log (c+d x)-2 b^2 d^2 p q r^2 x^2 \log (c+d x)+4 b^2 d^2 q^2 r^2 x^2 \log (c+d x)+2 a^2 d^2 q^2 r^2 \log ^2(c+d x)+4 a b d^2 q^2 r^2 x \log ^2(c+d x)+2 b^2 d^2 q^2 r^2 x^2 \log ^2(c+d x)-2 d^2 q r (a+b x)^2 \log (a+b x) \left (-p r+2 q r-2 p r \log (c+d x)+2 (p+q) r \log \left (\frac {b (c+d x)}{b c-a d}\right )-2 \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )\right )+2 b^2 c^2 p r \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )-4 a b c d p r \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )+2 a^2 d^2 p r \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )+4 a b c d q r \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )-4 a^2 d^2 q r \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )+4 b^2 c d q r x \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )-4 a b d^2 q r x \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )-4 a^2 d^2 q r \log (c+d x) \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )-8 a b d^2 q r x \log (c+d x) \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )-4 b^2 d^2 q r x^2 \log (c+d x) \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )+2 b^2 c^2 \log ^2\left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )-4 a b c d \log ^2\left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )+2 a^2 d^2 \log ^2\left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )-4 d^2 q (p+q) r^2 (a+b x)^2 \operatorname {PolyLog}\left (2,\frac {d (a+b x)}{-b c+a d}\right )}{4 b (b c-a d)^2 (a+b x)^2} \]

input
Integrate[Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r]^2/(a + b*x)^3,x]
 
output
-1/4*(b^2*c^2*p^2*r^2 - 2*a*b*c*d*p^2*r^2 + a^2*d^2*p^2*r^2 + 6*a*b*c*d*p* 
q*r^2 - 6*a^2*d^2*p*q*r^2 + 6*b^2*c*d*p*q*r^2*x - 6*a*b*d^2*p*q*r^2*x - 2* 
d^2*p*q*r^2*(a + b*x)^2*Log[a + b*x]^2 - 2*a^2*d^2*p*q*r^2*Log[c + d*x] + 
4*a^2*d^2*q^2*r^2*Log[c + d*x] - 4*a*b*d^2*p*q*r^2*x*Log[c + d*x] + 8*a*b* 
d^2*q^2*r^2*x*Log[c + d*x] - 2*b^2*d^2*p*q*r^2*x^2*Log[c + d*x] + 4*b^2*d^ 
2*q^2*r^2*x^2*Log[c + d*x] + 2*a^2*d^2*q^2*r^2*Log[c + d*x]^2 + 4*a*b*d^2* 
q^2*r^2*x*Log[c + d*x]^2 + 2*b^2*d^2*q^2*r^2*x^2*Log[c + d*x]^2 - 2*d^2*q* 
r*(a + b*x)^2*Log[a + b*x]*(-(p*r) + 2*q*r - 2*p*r*Log[c + d*x] + 2*(p + q 
)*r*Log[(b*(c + d*x))/(b*c - a*d)] - 2*Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r 
]) + 2*b^2*c^2*p*r*Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r] - 4*a*b*c*d*p*r*Lo 
g[e*(f*(a + b*x)^p*(c + d*x)^q)^r] + 2*a^2*d^2*p*r*Log[e*(f*(a + b*x)^p*(c 
 + d*x)^q)^r] + 4*a*b*c*d*q*r*Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r] - 4*a^2 
*d^2*q*r*Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r] + 4*b^2*c*d*q*r*x*Log[e*(f*( 
a + b*x)^p*(c + d*x)^q)^r] - 4*a*b*d^2*q*r*x*Log[e*(f*(a + b*x)^p*(c + d*x 
)^q)^r] - 4*a^2*d^2*q*r*Log[c + d*x]*Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r] 
- 8*a*b*d^2*q*r*x*Log[c + d*x]*Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r] - 4*b^ 
2*d^2*q*r*x^2*Log[c + d*x]*Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r] + 2*b^2*c^ 
2*Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r]^2 - 4*a*b*c*d*Log[e*(f*(a + b*x)^p* 
(c + d*x)^q)^r]^2 + 2*a^2*d^2*Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r]^2 - 4*d 
^2*q*(p + q)*r^2*(a + b*x)^2*PolyLog[2, (d*(a + b*x))/(-(b*c) + a*d)])/...
 
3.1.22.3 Rubi [A] (verified)

Time = 1.00 (sec) , antiderivative size = 545, normalized size of antiderivative = 0.86, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.226, Rules used = {2984, 2981, 17, 54, 2009, 2994, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\log ^2\left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{(a+b x)^3} \, dx\)

\(\Big \downarrow \) 2984

\(\displaystyle p r \int \frac {\log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{(a+b x)^3}dx+\frac {d q r \int \frac {\log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{(a+b x)^2 (c+d x)}dx}{b}-\frac {\log ^2\left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{2 b (a+b x)^2}\)

\(\Big \downarrow \) 2981

\(\displaystyle p r \left (\frac {d q r \int \frac {1}{(a+b x)^2 (c+d x)}dx}{2 b}+\frac {1}{2} p r \int \frac {1}{(a+b x)^3}dx-\frac {\log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{2 b (a+b x)^2}\right )+\frac {d q r \int \frac {\log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{(a+b x)^2 (c+d x)}dx}{b}-\frac {\log ^2\left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{2 b (a+b x)^2}\)

\(\Big \downarrow \) 17

\(\displaystyle p r \left (\frac {d q r \int \frac {1}{(a+b x)^2 (c+d x)}dx}{2 b}-\frac {\log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{2 b (a+b x)^2}-\frac {p r}{4 b (a+b x)^2}\right )+\frac {d q r \int \frac {\log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{(a+b x)^2 (c+d x)}dx}{b}-\frac {\log ^2\left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{2 b (a+b x)^2}\)

\(\Big \downarrow \) 54

\(\displaystyle p r \left (\frac {d q r \int \left (\frac {d^2}{(b c-a d)^2 (c+d x)}-\frac {b d}{(b c-a d)^2 (a+b x)}+\frac {b}{(b c-a d) (a+b x)^2}\right )dx}{2 b}-\frac {\log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{2 b (a+b x)^2}-\frac {p r}{4 b (a+b x)^2}\right )+\frac {d q r \int \frac {\log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{(a+b x)^2 (c+d x)}dx}{b}-\frac {\log ^2\left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{2 b (a+b x)^2}\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {d q r \int \frac {\log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{(a+b x)^2 (c+d x)}dx}{b}-\frac {\log ^2\left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{2 b (a+b x)^2}+p r \left (-\frac {\log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{2 b (a+b x)^2}+\frac {d q r \left (-\frac {1}{(a+b x) (b c-a d)}-\frac {d \log (a+b x)}{(b c-a d)^2}+\frac {d \log (c+d x)}{(b c-a d)^2}\right )}{2 b}-\frac {p r}{4 b (a+b x)^2}\right )\)

\(\Big \downarrow \) 2994

\(\displaystyle \frac {d q r \int \left (\frac {\log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right ) d^2}{(b c-a d)^2 (c+d x)}-\frac {b \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right ) d}{(b c-a d)^2 (a+b x)}+\frac {b \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{(b c-a d) (a+b x)^2}\right )dx}{b}-\frac {\log ^2\left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{2 b (a+b x)^2}+p r \left (-\frac {\log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{2 b (a+b x)^2}+\frac {d q r \left (-\frac {1}{(a+b x) (b c-a d)}-\frac {d \log (a+b x)}{(b c-a d)^2}+\frac {d \log (c+d x)}{(b c-a d)^2}\right )}{2 b}-\frac {p r}{4 b (a+b x)^2}\right )\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {d q r \left (-\frac {d \log (a+b x) \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{(b c-a d)^2}+\frac {d \log (c+d x) \log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{(b c-a d)^2}-\frac {\log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{(a+b x) (b c-a d)}-\frac {d p r \operatorname {PolyLog}\left (2,\frac {b (c+d x)}{b c-a d}\right )}{(b c-a d)^2}-\frac {p r}{(a+b x) (b c-a d)}+\frac {d p r \log ^2(a+b x)}{2 (b c-a d)^2}-\frac {d p r \log (c+d x) \log \left (-\frac {d (a+b x)}{b c-a d}\right )}{(b c-a d)^2}+\frac {d q r \operatorname {PolyLog}\left (2,-\frac {d (a+b x)}{b c-a d}\right )}{(b c-a d)^2}-\frac {d q r \log ^2(c+d x)}{2 (b c-a d)^2}+\frac {d q r \log (a+b x)}{(b c-a d)^2}+\frac {d q r \log (a+b x) \log \left (\frac {b (c+d x)}{b c-a d}\right )}{(b c-a d)^2}-\frac {d q r \log (c+d x)}{(b c-a d)^2}\right )}{b}-\frac {\log ^2\left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{2 b (a+b x)^2}+p r \left (-\frac {\log \left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{2 b (a+b x)^2}+\frac {d q r \left (-\frac {1}{(a+b x) (b c-a d)}-\frac {d \log (a+b x)}{(b c-a d)^2}+\frac {d \log (c+d x)}{(b c-a d)^2}\right )}{2 b}-\frac {p r}{4 b (a+b x)^2}\right )\)

input
Int[Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r]^2/(a + b*x)^3,x]
 
output
-1/2*Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r]^2/(b*(a + b*x)^2) + p*r*(-1/4*(p 
*r)/(b*(a + b*x)^2) + (d*q*r*(-(1/((b*c - a*d)*(a + b*x))) - (d*Log[a + b* 
x])/(b*c - a*d)^2 + (d*Log[c + d*x])/(b*c - a*d)^2))/(2*b) - Log[e*(f*(a + 
 b*x)^p*(c + d*x)^q)^r]/(2*b*(a + b*x)^2)) + (d*q*r*(-((p*r)/((b*c - a*d)* 
(a + b*x))) + (d*q*r*Log[a + b*x])/(b*c - a*d)^2 + (d*p*r*Log[a + b*x]^2)/ 
(2*(b*c - a*d)^2) - (d*q*r*Log[c + d*x])/(b*c - a*d)^2 - (d*p*r*Log[-((d*( 
a + b*x))/(b*c - a*d))]*Log[c + d*x])/(b*c - a*d)^2 - (d*q*r*Log[c + d*x]^ 
2)/(2*(b*c - a*d)^2) + (d*q*r*Log[a + b*x]*Log[(b*(c + d*x))/(b*c - a*d)]) 
/(b*c - a*d)^2 - Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r]/((b*c - a*d)*(a + b* 
x)) - (d*Log[a + b*x]*Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r])/(b*c - a*d)^2 
+ (d*Log[c + d*x]*Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r])/(b*c - a*d)^2 + (d 
*q*r*PolyLog[2, -((d*(a + b*x))/(b*c - a*d))])/(b*c - a*d)^2 - (d*p*r*Poly 
Log[2, (b*(c + d*x))/(b*c - a*d)])/(b*c - a*d)^2))/b
 

3.1.22.3.1 Defintions of rubi rules used

rule 17
Int[(c_.)*((a_.) + (b_.)*(x_))^(m_.), x_Symbol] :> Simp[c*((a + b*x)^(m + 1 
)/(b*(m + 1))), x] /; FreeQ[{a, b, c, m}, x] && NeQ[m, -1]
 

rule 54
Int[((a_) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[E 
xpandIntegrand[(a + b*x)^m*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d}, x] && 
 ILtQ[m, 0] && IntegerQ[n] &&  !(IGtQ[n, 0] && LtQ[m + n + 2, 0])
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 2981
Int[Log[(e_.)*((f_.)*((a_.) + (b_.)*(x_))^(p_.)*((c_.) + (d_.)*(x_))^(q_.)) 
^(r_.)]*((g_.) + (h_.)*(x_))^(m_.), x_Symbol] :> Simp[(g + h*x)^(m + 1)*(Lo 
g[e*(f*(a + b*x)^p*(c + d*x)^q)^r]/(h*(m + 1))), x] + (-Simp[b*p*(r/(h*(m + 
 1)))   Int[(g + h*x)^(m + 1)/(a + b*x), x], x] - Simp[d*q*(r/(h*(m + 1))) 
  Int[(g + h*x)^(m + 1)/(c + d*x), x], x]) /; FreeQ[{a, b, c, d, e, f, g, h 
, m, p, q, r}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1]
 

rule 2984
Int[Log[(e_.)*((f_.)*((a_.) + (b_.)*(x_))^(p_.)*((c_.) + (d_.)*(x_))^(q_.)) 
^(r_.)]^(s_)*((g_.) + (h_.)*(x_))^(m_.), x_Symbol] :> Simp[(g + h*x)^(m + 1 
)*(Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r]^s/(h*(m + 1))), x] + (-Simp[b*p*r*( 
s/(h*(m + 1)))   Int[(g + h*x)^(m + 1)*(Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r 
]^(s - 1)/(a + b*x)), x], x] - Simp[d*q*r*(s/(h*(m + 1)))   Int[(g + h*x)^( 
m + 1)*(Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r]^(s - 1)/(c + d*x)), x], x]) /; 
 FreeQ[{a, b, c, d, e, f, g, h, m, p, q, r, s}, x] && NeQ[b*c - a*d, 0] && 
IGtQ[s, 0] && NeQ[m, -1]
 

rule 2994
Int[Log[(e_.)*((f_.)*((a_.) + (b_.)*(x_))^(p_.)*((c_.) + (d_.)*(x_))^(q_.)) 
^(r_.)]^(s_.)*(RFx_), x_Symbol] :> With[{u = ExpandIntegrand[Log[e*(f*(a + 
b*x)^p*(c + d*x)^q)^r]^s, RFx, x]}, Int[u, x] /; SumQ[u]] /; FreeQ[{a, b, c 
, d, e, f, p, q, r, s}, x] && RationalFunctionQ[RFx, x] && IGtQ[s, 0]
 
3.1.22.4 Maple [F]

\[\int \frac {{\ln \left (e \left (f \left (b x +a \right )^{p} \left (d x +c \right )^{q}\right )^{r}\right )}^{2}}{\left (b x +a \right )^{3}}d x\]

input
int(ln(e*(f*(b*x+a)^p*(d*x+c)^q)^r)^2/(b*x+a)^3,x)
 
output
int(ln(e*(f*(b*x+a)^p*(d*x+c)^q)^r)^2/(b*x+a)^3,x)
 
3.1.22.5 Fricas [F]

\[ \int \frac {\log ^2\left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{(a+b x)^3} \, dx=\int { \frac {\log \left (\left ({\left (b x + a\right )}^{p} {\left (d x + c\right )}^{q} f\right )^{r} e\right )^{2}}{{\left (b x + a\right )}^{3}} \,d x } \]

input
integrate(log(e*(f*(b*x+a)^p*(d*x+c)^q)^r)^2/(b*x+a)^3,x, algorithm="frica 
s")
 
output
integral(log(((b*x + a)^p*(d*x + c)^q*f)^r*e)^2/(b^3*x^3 + 3*a*b^2*x^2 + 3 
*a^2*b*x + a^3), x)
 
3.1.22.6 Sympy [F]

\[ \int \frac {\log ^2\left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{(a+b x)^3} \, dx=\int \frac {\log {\left (e \left (f \left (a + b x\right )^{p} \left (c + d x\right )^{q}\right )^{r} \right )}^{2}}{\left (a + b x\right )^{3}}\, dx \]

input
integrate(ln(e*(f*(b*x+a)**p*(d*x+c)**q)**r)**2/(b*x+a)**3,x)
 
output
Integral(log(e*(f*(a + b*x)**p*(c + d*x)**q)**r)**2/(a + b*x)**3, x)
 
3.1.22.7 Maxima [A] (verification not implemented)

Time = 0.25 (sec) , antiderivative size = 755, normalized size of antiderivative = 1.19 \[ \int \frac {\log ^2\left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{(a+b x)^3} \, dx=-\frac {{\left (\frac {2 \, d^{2} f q \log \left (b x + a\right )}{b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}} - \frac {2 \, d^{2} f q \log \left (d x + c\right )}{b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}} + \frac {2 \, b d f q x - a d f {\left (p - 2 \, q\right )} + b c f p}{a^{2} b c - a^{3} d + {\left (b^{3} c - a b^{2} d\right )} x^{2} + 2 \, {\left (a b^{2} c - a^{2} b d\right )} x}\right )} r \log \left (\left ({\left (b x + a\right )}^{p} {\left (d x + c\right )}^{q} f\right )^{r} e\right )}{2 \, b f} + \frac {{\left (\frac {4 \, {\left (p q + q^{2}\right )} {\left (\log \left (b x + a\right ) \log \left (\frac {b d x + a d}{b c - a d} + 1\right ) + {\rm Li}_2\left (-\frac {b d x + a d}{b c - a d}\right )\right )} d^{2} f^{2}}{b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}} + \frac {2 \, {\left (p q - 2 \, q^{2}\right )} d^{2} f^{2} \log \left (d x + c\right )}{b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}} - \frac {b^{2} c^{2} f^{2} p^{2} - 2 \, {\left (p^{2} - 3 \, p q\right )} a b c d f^{2} + {\left (p^{2} - 6 \, p q\right )} a^{2} d^{2} f^{2} - 2 \, {\left (b^{2} d^{2} f^{2} p q x^{2} + 2 \, a b d^{2} f^{2} p q x + a^{2} d^{2} f^{2} p q\right )} \log \left (b x + a\right )^{2} + 4 \, {\left (b^{2} d^{2} f^{2} p q x^{2} + 2 \, a b d^{2} f^{2} p q x + a^{2} d^{2} f^{2} p q\right )} \log \left (b x + a\right ) \log \left (d x + c\right ) + 2 \, {\left (b^{2} d^{2} f^{2} q^{2} x^{2} + 2 \, a b d^{2} f^{2} q^{2} x + a^{2} d^{2} f^{2} q^{2}\right )} \log \left (d x + c\right )^{2} + 6 \, {\left (b^{2} c d f^{2} p q - a b d^{2} f^{2} p q\right )} x + 2 \, {\left ({\left (p q - 2 \, q^{2}\right )} b^{2} d^{2} f^{2} x^{2} + 2 \, {\left (p q - 2 \, q^{2}\right )} a b d^{2} f^{2} x + {\left (p q - 2 \, q^{2}\right )} a^{2} d^{2} f^{2}\right )} \log \left (b x + a\right )}{a^{2} b^{2} c^{2} - 2 \, a^{3} b c d + a^{4} d^{2} + {\left (b^{4} c^{2} - 2 \, a b^{3} c d + a^{2} b^{2} d^{2}\right )} x^{2} + 2 \, {\left (a b^{3} c^{2} - 2 \, a^{2} b^{2} c d + a^{3} b d^{2}\right )} x}\right )} r^{2}}{4 \, b f^{2}} - \frac {\log \left (\left ({\left (b x + a\right )}^{p} {\left (d x + c\right )}^{q} f\right )^{r} e\right )^{2}}{2 \, {\left (b x + a\right )}^{2} b} \]

input
integrate(log(e*(f*(b*x+a)^p*(d*x+c)^q)^r)^2/(b*x+a)^3,x, algorithm="maxim 
a")
 
output
-1/2*(2*d^2*f*q*log(b*x + a)/(b^2*c^2 - 2*a*b*c*d + a^2*d^2) - 2*d^2*f*q*l 
og(d*x + c)/(b^2*c^2 - 2*a*b*c*d + a^2*d^2) + (2*b*d*f*q*x - a*d*f*(p - 2* 
q) + b*c*f*p)/(a^2*b*c - a^3*d + (b^3*c - a*b^2*d)*x^2 + 2*(a*b^2*c - a^2* 
b*d)*x))*r*log(((b*x + a)^p*(d*x + c)^q*f)^r*e)/(b*f) + 1/4*(4*(p*q + q^2) 
*(log(b*x + a)*log((b*d*x + a*d)/(b*c - a*d) + 1) + dilog(-(b*d*x + a*d)/( 
b*c - a*d)))*d^2*f^2/(b^2*c^2 - 2*a*b*c*d + a^2*d^2) + 2*(p*q - 2*q^2)*d^2 
*f^2*log(d*x + c)/(b^2*c^2 - 2*a*b*c*d + a^2*d^2) - (b^2*c^2*f^2*p^2 - 2*( 
p^2 - 3*p*q)*a*b*c*d*f^2 + (p^2 - 6*p*q)*a^2*d^2*f^2 - 2*(b^2*d^2*f^2*p*q* 
x^2 + 2*a*b*d^2*f^2*p*q*x + a^2*d^2*f^2*p*q)*log(b*x + a)^2 + 4*(b^2*d^2*f 
^2*p*q*x^2 + 2*a*b*d^2*f^2*p*q*x + a^2*d^2*f^2*p*q)*log(b*x + a)*log(d*x + 
 c) + 2*(b^2*d^2*f^2*q^2*x^2 + 2*a*b*d^2*f^2*q^2*x + a^2*d^2*f^2*q^2)*log( 
d*x + c)^2 + 6*(b^2*c*d*f^2*p*q - a*b*d^2*f^2*p*q)*x + 2*((p*q - 2*q^2)*b^ 
2*d^2*f^2*x^2 + 2*(p*q - 2*q^2)*a*b*d^2*f^2*x + (p*q - 2*q^2)*a^2*d^2*f^2) 
*log(b*x + a))/(a^2*b^2*c^2 - 2*a^3*b*c*d + a^4*d^2 + (b^4*c^2 - 2*a*b^3*c 
*d + a^2*b^2*d^2)*x^2 + 2*(a*b^3*c^2 - 2*a^2*b^2*c*d + a^3*b*d^2)*x))*r^2/ 
(b*f^2) - 1/2*log(((b*x + a)^p*(d*x + c)^q*f)^r*e)^2/((b*x + a)^2*b)
 
3.1.22.8 Giac [F]

\[ \int \frac {\log ^2\left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{(a+b x)^3} \, dx=\int { \frac {\log \left (\left ({\left (b x + a\right )}^{p} {\left (d x + c\right )}^{q} f\right )^{r} e\right )^{2}}{{\left (b x + a\right )}^{3}} \,d x } \]

input
integrate(log(e*(f*(b*x+a)^p*(d*x+c)^q)^r)^2/(b*x+a)^3,x, algorithm="giac" 
)
 
output
integrate(log(((b*x + a)^p*(d*x + c)^q*f)^r*e)^2/(b*x + a)^3, x)
 
3.1.22.9 Mupad [F(-1)]

Timed out. \[ \int \frac {\log ^2\left (e \left (f (a+b x)^p (c+d x)^q\right )^r\right )}{(a+b x)^3} \, dx=\int \frac {{\ln \left (e\,{\left (f\,{\left (a+b\,x\right )}^p\,{\left (c+d\,x\right )}^q\right )}^r\right )}^2}{{\left (a+b\,x\right )}^3} \,d x \]

input
int(log(e*(f*(a + b*x)^p*(c + d*x)^q)^r)^2/(a + b*x)^3,x)
 
output
int(log(e*(f*(a + b*x)^p*(c + d*x)^q)^r)^2/(a + b*x)^3, x)